Forum → Did U observe something! Trunks and Goten have no tails.

Post

[[Category:{{{1}}}|Did U observe something! Trunks and Goten have no tails.]]

Trunks and Goten have no tails.And don't tell me half saiyans have no tail,b'coz even Gohan had a tail.

And even if Chichi & Bulma had cut it during their birth,they would have grown it back,just like Gohan's and Goku's Tail.

And this simple calculation gives away the mistake,

1/2 Saiyan + 1/2 Saiyan=2/2 Saiyan(Pure Saiyan).

Thus,

Goten + Trunks=Gotenks.

who must have a tail,coz He is a Pure Saiyan.

There is no reason that they could have been removed soon after birth to prevent them turning into a great ape...

Also, 1/2 saiyans do have tails, look at Gohan!

In response to the fustion of Goten and Trunks, a half saiyan + half saiyan fuision results in a half saiyan. They are all half human and half saiyan. If you merged a full saiyan and a half saiyan, you'd get a 3/4 saiyan, you simply average their percentage.

Where the hell you got that idea?

It could be that they cut off their tail and was never shown.

You two half human half saiyan. fi the yfuse the remain half human half saiyan. their power is enlarged, yes but htey wont become full sayan or 3/4 sayain.

this may be a SPOILER but the real resean they dont have tails is that the Author forgot to drew them.

AnswerEdit

Its very simple. The author has said that the saiyan tail is a recessive trait and therefore not present in Goten and Trunks. TBH i think its bc the author stopped caring about the ape factor and made this explanation after the fact.Jpark0015 20:39, December 20, 2011 (UTC)

Toriyama sucks at biology; tails are not a recessive trait, as that would mean Gohan couldn't have one. They were continually cut off every time they grew back. Also, retard OP can't do math. --DARK 20:46, December 20, 2011 (UTC)

If you fuse 1/2 saiyan and 1/2 half human together witha 1/2 saiyan and 1/2 human, then you would get a 1/2 saiyan 1/2 human person because they have both the saiyan and human DNA in them.